# Taking Derivatives with Vandermonde Matrices¶

In [1]:
import numpy as np
import numpy.linalg as la
import matplotlib.pyplot as pt


Here are a few functions:

In [205]:
if 1:
def f(x):
return np.sin(5*x)
def df(x):
return 5*np.cos(5*x)
elif 0:
gamma = 0.15
def f(x):
return np.sin(1/(gamma+x))
def df(x):
return -np.cos(1/(gamma+x))/(gamma+x)**2
else:
def f(x):
return np.abs(x-0.5)
def df(x):
# Well...
return -1 + 2*(x<=0.5).astype(np.float)

In [206]:
x_01 = np.linspace(0, 1, 1000)
pt.plot(x_01, f(x_01))

Out[206]:
[<matplotlib.lines.Line2D at 0x7f560bd55e48>]
In [246]:
degree = 4
h = 1

nodes = 0.5 + np.linspace(-h/2, h/2, degree+1)
nodes

Out[246]:
array([ 0.  ,  0.25,  0.5 ,  0.75,  1.  ])

Build the gen. Vandermonde matrix and find the coefficients:

In [247]:
V = np.array([
nodes**i
for i in range(degree+1)
]).T

In [256]:
coeffs = la.solve(V, f(nodes))


Evaluate the interpolant:

In [249]:
x_0h = 0.5+np.linspace(-h/2, h/2, 1000)

In [250]:
interp_0h = 0*x_0h
for i in range(degree+1):
interp_0h += coeffs[i] * x_0h**i

In [251]:
pt.plot(x_01, f(x_01), "--", color="gray", label="$f$")
pt.plot(x_0h, interp_0h, color="red", label="Interpolant")
pt.plot(nodes, f(nodes), "or")
pt.legend(loc="best")

Out[251]:
<matplotlib.legend.Legend at 0x7f560b9caf98>

Now build the gen. Vandermonde matrix $V'=$Vprime of the derivatives:

In [252]:
def monomial_deriv(i, x):
if i == 0:
return 0*x
else:
return i*nodes**(i-1)

Vprime = np.array([
monomial_deriv(i, nodes)
for i in range(degree+1)
]).T


Compute the value of the derivative at the nodes as fderiv:

In [257]:
fderiv = Vprime.dot(la.inv(V)).dot(f(nodes))


And plot vs df, the exact derivative:

In [258]:
pt.plot(x_01, df(x_01), "--", color="gray", label="$f$")
pt.plot(nodes, fderiv, "or")
pt.legend(loc="best")

Out[258]:
<matplotlib.legend.Legend at 0x7f560b9168d0>
• Why don't we hit the values of the derivative exactly?
• Do an accuracy study.
In [255]:
print(np.max(np.abs(df(nodes) - fderiv)))

1.85604897639